Leah4sci - 2016-02-10
Leah4sci.com/redox presents: Carbonyl Reduction using NaBH4 - Sodium Borohydride. Reaction, Mechanism and examples. Need help with orgo? Download my free guide '10 Secrets to Acing Organic Chemistry' HERE: http://leah4sci.com/orgo-ebook/ This video breaks down the reducing agent NaBH4 to help you understand its reactivity with carbonyl compounds. This is video 6 in the Organic Chemistry Oxidation/Reduction video series. Catch the entire series along with my redox practice quiz and cheat sheet on my website: http://leah4sci.com/redox For more in-depth review including practice problems and explanations, check out my online membership site: http://studyhall.leah4sci.com/join For private online tutoring visit my website: http://leah4sci.com/organic-chemistry-tutor/ Finally, for questions and comments, find me on social media here: Facebook: https://www.facebook.com/Leah4sci Twitter: https://twitter.com/Leah4Sci Google+ https://plus.google.com/u/0/+LeahFisch Pinterest: http://www.pinterest.com/leah4sci/
Thank you ma'am👏 this video is very helpful from the exam prospective. Your chemistry is outstanding..
Your channel is help to make chemistry very easy... Specially 2nd year chemistry Thank you 😊😊 so much..
Thanks so much for your kind words, and you're very welcome!
Wish I've discovered your channel back when I had second year chemistry! Great video!
Better late than never. Glad you enjoyed it!
@Leah4sci you guys are studied this at second year .
I am studiying this in 12 th class .
For entrance exam called Jee advanced
I just came across your channel as im studying for my lab and I can't say this enough, this is SUCH a good video !!! thank you !!!
Awww, thanks for your kind words! Glad you like it!
Legend 👏 explained well, even elementary kids can be able to understand it.. thanks gifted
Thanks so much for your kind words, I appreciate it!
@Leah4sci you're welcome.. these words comming from my heart 💓, l really appreciate you, to be honest, you have a gift that our good Lord put it in you is that, your single word in explaining any problems in organic chemistry makes more sense, meaning and your Vocal voice is quite cool where it diffuse in to our minds easily without spending much time.. gifted, humble, humility,respect, potential are now your character because Leah4science.. can explain more concerpt in less time so gifted and talented, will explain not too fast or too quite but in good middle mood so humble, humility and in respectful manner,,, thanks Leah for imparting knowledge in to my brain... I Simon Peapo from NEW GUINEA ISLAND (PNG) major in chemistry 3rd year student from university Of Papua New Guinea
very useful for my m.sc chemistry exam mam....thanks a lot
thank you! it' s very easy to understand your teaching. It's help a lot
this video explains the science not leaving out any information. very good! thank you :)
My pleasure, glad it was helpful!
Thank you for your nice education, It's really useful to me as a student of engineering college in Korea
Glad it was helpful!
Very good explanation! Thank you very much!
Thanks! You're welcome Kaio! :)
This video was helped me big time. Thank you
You're welcome!
Your videos are always remarkable! Thank You! :) :)
You're welcome :)
thankyou so much
finally someone who cleared this doubt effortlessly
love from india
So happy to help you!
I have a lab on this In an hour :) this makes a lot of sense now!
Same here!
Hi Leah thanks for your video..Really helped me a lot. What would be the purpose of adding NAOH to the solution during lab?
That's not exactly what this video covers. But as a base, NaOH is a proton acceptor and will choose to pull a proton from another compound, when possible.
I had a lab where we reduced an Imine with NaBH4 and during this step in the lab there was bubbling (and also dissolving of the imine in the solution it was in). I was wondering if hydrogen gas was a by product of the reduction and caused the bubbling. Might hydrogen gas come from this? and if more info's need i could probably delve into it more
I'm sorry but I don't offer tutoring through YouTube comments. For help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
Mam i understood all the steps but in last where BH3 Gone after leaving H- to Carbonyl group ??
Very Clear ~~ thank you !
Hi, can i ask a what is the major product for the reaction of sodium borohydrite with propan-2-ene. Thank you!
I don't believe that particular reaction is discussed in this video, and unfortunately I do no offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website http://leah4sci.com/contact/
Great video, I´m from Argentina and I couldn´t find an explanation for NaBH4
Glad it helped!
Can you tell me the mechanism of nitrobenzene and NaBH4 reaction plz
Great video. At 3:37 why will it reduce the aldehyde and not the ester?
Super late and may not be helpful but NaBH4 is only a mild and selective reducing agent, and reacts with esters very slowly at room temp which is why it may not react with the ester.
@K C Thanks a lot sir/mam for your explanation. I got it.
Excellent video
This video is very nice.
Thank u so much for this video
You're welcome!
@Leah4sci I have some questions, u can help me.
When react alcohole with thionyl chloride to product alkyl halide
what are catalyst and solvent I will use for this reaction
Thank you 😇
thank you so much!!!
Hey Leah, while explaining the mechanism you said Boron contains a negative charge but if we see the electronegativity chart the Hydrogen has electronegativity of 2.1 which is slightly more than that of Boron's (2.0). Therefore, the charge on hydrogen should be partially negative as it will pull the electrons from Boron on which charge should become partially positive. Can you please explain why you represented a negative charge on Boron?
Great Explanation by the way!!
Yes, of course! I said that boron has a formal charge of 1. That's because it is surrounded by one more electron than what a typical boron atom would have in its valence shell. I do recognize that hydrogen is more electronegative, and you'll see I explain that the hydride is negative around 0:40. You can think of BH4^ as a neutral BH3 attached to a negative hydrogen atom, for the purposes of this reaction. To read more about formal charge, you can see my tutorial at https://leah4sci.com/formal-charge-formula-and-shortcut/
if acid and ester both functional group present in one molecule... BH4 react with acid not ester why????
see the video comparing LiAlH4 to NaBH4 in this series: http://leah4sci.com/redox
Thank you... Very helpful clz
You're welcome 😊
truly amazing
Glad you like it!
Thanks i needed to check if ch3ona was indeed forming.
You're welcome
Nice video
Thanks!
nice lectur
Thank you for the video, I forgot about the Na + ion hahahaha
Can't forget that! Glad I could help
👏👏
Glad you like it!
MAM , NaBH4 in ACIDIC Methylene blue how to react . mam if you have solve this reaction then mentioned me plz on the vadio
I have no plans to do a video on that anytime soon, sorry
Suprrrr......❣️❣️
Woohoo!
I have a question, what do you mean by looking for a nucleophilic attack rather than basic? *isn't a nucleophile a base? 1:08
not exactly! They can be but the definition is determined by context
thank u so mush for this
you're very welcome
Hey does NaBH4 attacks from backside?
Thank you
You're welcome
which Bond will Break In Butanone By Oxidation...Tell Me which Bond and also with Reason..Anyone here
For help with this question and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
@Leah4sci thanks Mam
Can I cite this ?
Yes, just give full credit to my channel.
ur video made my day
Glad I could help :)
Easy as pi (bonds)
Sodium has a weak reducing agent
I’m sorry, but I don’t understand your question. Is there a specific point in the video you are concerned about?
In the example with 2 carbonyls why is the aldehyde reduced and not the ketone? I have an example where the structure has a ketone and a carboxylic acid and I'm not sure which one will be reduced.
This example does not have a ketone. Rather, it has an aldehyde group along with an ESTER. An ester is much less reactive than an aldehyde. In fact, its carbonyl group is only weakly electrophilic. Since NaBH4 is a weak reducing agent, we see it selectively choose the ‘easier’ carbonyl to reduce. In this case, that’s the aldehyde. Hope this clears it up for you.
Chemistry exam tomorrow. Lets have some fun
How'd it turn out?
good
Your voice is like the girl who says...
Hey you yes you! 😂
hahaha! thanks? I hope the video helped you.
@Leah4sci don't get offended I was actually talking about the girl in adult sites.😅
Malek Ayoub - 2016-02-11
Thank you so much for such a great video! Actually I never thought about the Mechanism of NaBH4, Its great to know for MCAT!